Red Bull celebrate titles with doughnuts in Dubai

2013 F1 season

http://youtu.be/LZrQqXKKAwM

Not content with Sebastian Vettel’s post-race celebration doughnuts in India – for which the team were fined ??25,000 – Red Bull continued their championship celebrations in Dubai.

David Coulthard performed some more doughnuts on the helipad of the Burj Al Arab luxury hotel, 210 metres above the Emirati capital.

Red Bull clinched their fourth consecutive constructors’ championship in India and Vettel won the drivers’ title for the fourth year in a row.

http://youtu.be/LCezxngqO9o

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Image ?? Red Bull/Getty

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39 comments on Red Bull celebrate titles with doughnuts in Dubai

  1. Strontium (@strontium) said on 31st October 2013, 15:36

    Wow! Certainly seems odd that they took a car and team up there just for that…

    Even so, hopefully the BBC will have something to show /:)

  2. paul rodriguez said on 31st October 2013, 15:43

    The front left doesn’t move an inch from its vertical axis…

    • OmarR-Pepper (@omarr-pepper) said on 31st October 2013, 22:39

      Anyway, I wouldn’t do it, not even for a night in that 7 star hotel!!!!!

    • Reflexzero said on 1st November 2013, 20:40

      Yeah, DC has the steering wheel hard over, but the inside front wheel is locked straight ahead, while the outboard front is turned in. Must have disengaged the steering and locked the left front into a pivot, probably using some sort of aircraft tie-down location in the helipad.

  3. wasiF1 (@wasif1) said on 31st October 2013, 16:26

    I think lots of driver and team personal are staying in the hotel so for them it will be FUN

  4. New found respect for DC there. My fear of heights kicked into over drive just *watching* that video! :-o

  5. Breno (@austus) said on 31st October 2013, 23:57

    Can someone gues-timate the terminal speed of F1 car if it fell down? I mean, would it be too different from what we usually see?

    • Hollidog said on 1st November 2013, 3:06

      231km/h or 64.16m/s
      Its pretty simple physics, Velocity(final)^2=Velocity(initial)^2+2xAccelerationxDistance, or V.final^2=0^2+2×9.8×210, which gives 4116, but you have to take the square root so it becomes 64.156 then times by 3.6 to change to km/h giving 230.96.

      Perfectly survivable by todays standards I would say, though that doesnt factor that the ground wont absorb much of the energy when it hits.

      Gotta love physics!

  6. Ron (@rcorporon) said on 1st November 2013, 1:31

    This is the type of stuff that led me to cheer for RBR in the first place… they just seem to like to have fun!

  7. Hessu said on 1st November 2013, 11:51

    You can clearly see that the left front wheel is attached to a rotating plate, for example at 0:50 of the video. Still, a cool stunt!

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